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Question

A stone is thrown vertically upward with an initial velocity vo. The distance travelled in time 1.5vog is


A
v2o2g
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B
3v2o8g
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C
5v2o8g
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D
None of these 
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Solution

The correct option is C 5v2o8g
Velocity of particle will become zero in time,
to=vog (by using first equation of motion)
The given time t=1.5vog is greater than the time to=vog
Hence, The total distance travelled will be the sum of the distance travelled in time to and (tto)
Distance travelled =st+stto
By using third equation of motion, 02=v2o2gst
st=v2o2g
For stt0, using second equation of motion, stto=(0×t)+12g(tto)2 
stto=12g(1.5vogvog)2
stto=12g(.5vo)2
stto=v2o8g
Distance travelled =v2o2g+v2o8g5v2o8g

Physics

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