You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Tension in a String

A stone of ma...

Question

A stone of mass $0.2 k g$ is tied to one end of a thread of length $0.1 m$ whirled in a vertical circle. When the stone is at the lowest point of circle, tension in thread is $52 N$ , then velocity of the stone will be:

4 m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 m / s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6 m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7 m / s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $5 m / s$
$T - m g = \frac{{m v}^{2}}{r} T = \frac{{m v}^{2}}{r} + m g 52 = 0.2 (10) + \frac{0.2 (v^{2})}{0.1} 2 v^{2} = 52 - 2 = 50 v = 5 m / s e c$

Suggest Corrections

Similar questions

Q. A stone of mass

1 k g

is tied to the end of a string of

1 m

length. It is whirled in a vertical circle. If the velocity of the stone at the top be

4 m / s

. What is the tension in the string (at that instant)?

Q. A stone of mass

1 k g

is tied of the end of a string

1 m

long. It is whirled in a vertical circle. If the velocity of stone at the top is

4 m / s

. What is the tension in the string at the lowest point?

Take

g = 10 m / s^{2}

Q. A small stone of mass

200 g

is tied to one end of a string of length

80 cm

. Holding the other end in the hand, the stone is whirled in a vertical circle. What is the minimum speed that needs to be imparted at the lowest point such that the stone is just able to complete the vertical circle?(Take

g = 10 m / s^{2}

)

A stone of mass 1 kg is tied with a string and it is whirled in a vertical circle of radius 1m. If tension at the highest point is 14N, then velocity at lowest point will be:

Q. A stone of mass

1 kg

tied to a light string of length

\frac{10}{3} m

is whirled in a vertical circle. If the ratio of the maximum tension to minimum tension is 4 and

g = 10 {m/s}^{2}

, then the speed of the stone at the highest point of the circle is

Join BYJU'S Learning Program

A stone of mass 0.2kg is tied to one end of a thread of length 0.1m whirled in a vertical circle. When the stone is at the lowest point of circle, tension in thread is 52N, then velocity of the stone will be:

The correct option is B 5m/sT−mg=mv2rT=mv2r+mg52=0.2(10)+0.2(v2)0.12v2=52−2=50v=5m/sec

A stone of mass $0.2 k g$ is tied to one end of a thread of length $0.1 m$ whirled in a vertical circle. When the stone is at the lowest point of circle, tension in thread is $52 N$ , then velocity of the stone will be:

The correct option is B $5 m / s$
$T - m g = \frac{{m v}^{2}}{r} T = \frac{{m v}^{2}}{r} + m g 52 = 0.2 (10) + \frac{0.2 (v^{2})}{0.1} 2 v^{2} = 52 - 2 = 50 v = 5 m / s e c$