A stone of mass $0.5 k g$ is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

4.9 N

vertically upward

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4.9 N

vertically downward

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0.98 N

vertically downward

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9.8 N

vertically downward

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Solution

The correct option is B $4.9 N$ vertically downward
The stone experiences an acceleration due to gravity $(g)$ vertically downwards, $g = 9.8 m / s^{2}$
Mass of stone $m = 0.5$ kg
Force acting on the stone $F = m g$
$∴$ $F = 0.5 \times 9.8 = 4.9 N$ (vertically downward)

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A stone of mass 0.5 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

The correct option is B 4.9 N vertically downwardThe stone experiences an acceleration due to gravity (g) vertically downwards,g=9.8m/s2Mass of stone m=0.5 kgForce acting on the stone F=mg∴ F=0.5×9.8=4.9N (vertically downward)

A stone of mass $0.5 k g$ is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

The correct option is B $4.9 N$ vertically downward
The stone experiences an acceleration due to gravity $(g)$ vertically downwards, $g = 9.8 m / s^{2}$
Mass of stone $m = 0.5$ kg
Force acting on the stone $F = m g$
$∴$ $F = 0.5 \times 9.8 = 4.9 N$ (vertically downward)