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Question

A stone of relative density K is released from rest on the surface of a lake. If various effects are ignored, the stone sinks in water with an acceleration of



Your Answer
A

g(1 – K)

Your Answer
B

g(1 + K)

Correct Answer
C

Your Answer
D


Solution

The correct option is A


The net force acting on the stone in a downward direction would be equal to F = Vσg – Vρg, where m is the mass of the stone. The force acting downwards would be equal to Vσg due to its weight and the force acting upwards would be equal to Vρg due to the buoyant force. Hence we get

F=VσgVρg=Vσg(1ρσ)=mg(1ρσ)=mg(11K)Thus,a=g(11K)

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