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Question

A stone projected with a speed u at an angle θ  with the horizontal reaches maximum height H1.  When it is projected with speed u at an angle 90θ   with the horizontal, it reaches maximum height H2.  The relation between the horizontal range R of the projectile, H1 and H2 is 


A
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B
R = 4(H1 - H2)
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C
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D
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Solution

The correct option is A

H1 = u2sin2θ2g and
H2 = u2sin2(90θ)2g = u2cos2θ2g
H1H2 = u2sin2θ2g × u2cos2θ2g = (u2sin2θ)216g2= R216
R = 4 H1H2


Physics

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