A storage battery of emf 8-0 V and internal resistance 0-5- is being charged by a 120 V dc supply using a series resistor of 15-5- What is the terminal voltage of the battery during charging- What is the purpose of having a series resistor in the charging circuit-

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Standard XII

Physics

Physical Quantities

A storage bat...

Question

A storage battery of emf 8.0 V and internal resistance $0.5 Ω$ is being charged by a 120 V dc supply using a series resistor of $15.5 Ω$ . What is the terminal voltage of the battery during charging? What is the purpose of having a series resistor in the charging circuit?

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Solution

$E = 8 V$ , internal resistance $R_{1} = 0.5 Ω$
$V = 120 V$ , resistance $R_{2} = 15.5 Ω$
Effective voltage $V^{^{'}} = V - E = 112 V$
$I = \frac{V^{^{'}}}{R_{1} + R_{2}} = 7 A$
Voltage across $R_{1} = I R_{1} = 3.5 V$
Terminal voltage $= 8 + 3.5 = 11.5 V$
Series resistor in the charging circuit limits the current drawn from the external source.

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A storage battery of emf 8.0 V and internal resistance 0.5Ω is being charged by a 120 V dc supply using a series resistor of 15.5Ω. What is the terminal voltage of the battery during charging? What is the purpose of having a series resistor in the charging circuit?

E=8V, internal resistance R1=0.5ΩV=120V, resistance R2=15.5ΩEffective voltage V′=V−E=112 VI=V′R1+R2=7 AVoltage across R1=IR1=3.5 VTerminal voltage =8+3.5=11.5 VSeries resistor in the charging circuit limits the current drawn from the external source.

A storage battery of emf 8.0 V and internal resistance $0.5 Ω$ is being charged by a 120 V dc supply using a series resistor of $15.5 Ω$ . What is the terminal voltage of the battery during charging? What is the purpose of having a series resistor in the charging circuit?