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Question

A straight rod AB of mass M and length L is placed on a frictionless horizontal surface. a horizontal force having constant magnitude F and a fixed direction starts acting at the end A. The rod is initially perpendicular to the force. Find the initial acceleration of end B.

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Solution

Initially the rod is perpendicular to the force . So the moment of force about end B is =F.AB=F.L
The moment of inertia of the rod about a axis passing through and B and perpendicular to its length is.
I=13ML2
If initil acceleration of rod α
Torque applied on the rod about B = Moment of force about B
Iα=F.L
13ML2α=F.L
α=3FML

957279_760886_ans_547a1b4fb63f4b4b827358db83b84c5a.png

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