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A stream of photons having energy 5 eV each impinges on a potassium surface. The work function of potassium is 3.0 eV. The emerging photo - electrons are slowed down by a copper plate placed 5 mm away. If the potential difference between the two metal plates is 1 V, the maximum distance (in mm) the electrons can move away from the potassium surface before being turned back is


Solution

Relation between maximum kinetic energy and work function is KEmax=TEϕ=hvϕ=53=2.0 eV.
Using WE theorem: Fs=KEmax
Here Electrostatic force F=eE=eVd
s=KEF=KEe(Vd)=(KE)deV=2×51=10 mm

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