Question

# A student connects four 1/4 ohm cells in series but one cell has its terminals reversed. If each cell has an emf of 1.5 V and the external resistance is 2 ohm , then the current flowing is

A
1A
B
1.5 A
C
2.5 A
D
zero

Solution

## The correct option is A 1AEquivalent emf in series combination is given by,$$E_{eq} = E_{1}+E_{2}+....$$In the given question it will be,$$E_{eq}=1.5+1.5-1.5+1.5$$$$R_{eq}=\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}+\dfrac{1}{4}+2$$ ohmNow, $$I=\dfrac{E_{eq}}{R_{eq}}$$$$I=1A$$Physics

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