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Question

A student makes an error of 1% in measuring length of pendulum and negative error of 3% in value of time periods. The percentage error in the measurement of ā€˜gā€™ will be


A
5%
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B
1%
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C
7%
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D
2%
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Solution

The correct option is C 7%
g=4π21T2
Δ9g×100=Δll×100+2(ΔTT×100)
=1%+2(3%)
=7%

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