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Question

A student measured the length of a rod and wrote it as 3.50cm. Which instrument did he use to measure it?

A
A screw gauge having 100 division in the circular scale and pitch as 1mm.
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B
A screw gauge having 50 divisions in the circular scale and pitch as 1mm.
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C
A meter scale.
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D
A vernier calliper where the 10 divisions in vernier scale scale matches with 9 in main scale and main scale has 10 divisions in 1cm.
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Solution

The correct option is C A vernier calliper where the 10 divisions in vernier scale scale matches with 9 in main scale and main scale has 10 divisions in 1cm.
Least count of vernier calliper is110mm=0.1mm=0.01cm
f student measures 3.50cm, it means that there is an uncertainly of order 0.01cm, For vernier scale with 1MSD=1mm

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