Question

A student performs a titration with different burettes and finds titre values of $25.2$ ml, $25.25$ ml and $25.0$ ml. The number of significant figures in the average titre value is :

• A. $3$
• B. $4$
• C. $6$
• D. $8$

Answer 1

The correct option is A $3$

We have $25.20,25.25$ and $25.00$ ml.

Average= $\frac{25.20+25.25+25.00}{3}$
= $\frac{75.45}{3}$

= $25.15=25.1$

In case of division, the final answer will contain as many significant figures as there are in an number with least significant numbers.

So, the significant number is $3$.