Question

# A submarine emits a sonar pulse, which returns from an underwater cliff in $1.02s$. If the speed of sound in salt water is $1531m{s}^{-1}$, how far away is the cliff?

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Solution

## Step 1: GivenTime taken by sonar pulse to return, $t=1.02s$Time taken by sonar pulse to hit the cliff, $t\text{'}=\frac{t}{2}=0.51s$Speed of sound in salt water = $1531m{s}^{-1}$Step 2: Formula used and calculationDistance of the cliff from the submarine $\phantom{\rule{0ex}{0ex}}=speed×time\phantom{\rule{0ex}{0ex}}=1531×0.51\phantom{\rule{0ex}{0ex}}=780.51m$The cliff is $780.51m$ far from the submarine.

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