Question

A substance undergoes first order decomposition involving two parallel first order reaction as :

The mol percent of B in the product is :

• A. 23.17
• B. 76.83
• C. 30.16
• D. 69.84

Answer 1

The correct option is B

76.83

$\frac{k_1\times 100}{k_1+k_2}=\frac{1.26\times {10}^{-4}\times 100}{1.25\times {10}^{-4}+3.80\times {10}^{-5}}=76.83$