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Question

A system has two charges qA=2.5×107C and qB=2.5×107C is located at points A(0,0,15)cm and B(0,0,+15cm) respectively. What is the total charge and electric dipole moment vector of the system?


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Solution

Step 1. Given Data,

qA=2.5×107C
qB=2.5×107

A(0,0,-15cm)andB(0,0,+15cm)

Step 2. Formula used,

Dipole moment= P=q×d

d is the length of the dipole

q is the given charge

Step 3. Calculating the total charge,

The amount of charge at A, qA=2.5×107C
The amount of charge at B, qB=2.5×107
The total charge of the system is q=qA+qB=2.5×107C=0

Hence the total charge is 0.

Step 4. Calculating the electric dipole moment


Distance between points A and B,
d=15+15=30cm=0.3m

The electric dipole moment of the system,

P=qA×d=2.5×107×0.3=7.5×108cm along the positive z-axis.
Hence, the electric dipole moment of the system is 7.5×108 along the positive z-axis.


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