Question

# A system is provided with $50$Joules of heat and the work done on the system is $10$joules. What is the change in the internal energy of the system in Joules?

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Solution

## Step 1: GivenHeat provided to the system, q = $+50J$Work done on the system, W = $+10J$Step 2: Formula used and calculationchange in internal energy = heat provided + work done$⇒∆U=q+W\phantom{\rule{0ex}{0ex}}⇒∆U=50J+10J\phantom{\rule{0ex}{0ex}}⇒∆U=60J$Hence, change in internal energy is $60J$.

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