Question

A TABLE CLOCK HAS ITS MINUTE HAND 5.0 CM LONG. THE AVERAGE VELOCITY OF THE TIP OF THE MINUTE HAND BETWEEN 6:00 AM TO 6:30 PMIS-

Answer 1

$$\begin{gathered} \mathrm{Displacement}=5\mathrm{cm}+5\mathrm{cm}=10\mathrm{cm}=0.10\mathrm{m} \\ \mathrm{Time}\mathrm{taken}\mathrm{during}\mathrm{this}\mathrm{displacement}=12\mathrm{hours}\mathrm{and}30\mathrm{minutes}=(12\times 60\times 60)+(30\times 60)=45000\sec \\ \mathrm{Average}\mathrm{velocity}=\frac{\mathrm{Displacement}}{\mathrm{Time}}=\frac{0.10}{45000}=\frac{10\times {10}^{-2}}{45\times {10}^3}=2.22\times {10}^{-6}\mathrm{m}/\mathrm{s} \end{gathered}$$