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Question

A target element A is bombarded with electrons and the wavelengths of the characteristic spectrum are measured. A second characteristic spectrum is also obtained because of an impurity in the target. The wavelength of the Kα  lines are 196 pm (element A) and 169 pm (impurity). If the atomic number of impurity is z=(10x1). Find the value of x.
(atomic number of element A is 27).


Solution

From Moseley’s law,
v=a(zb)
v=Cλ;b=1,a=3Rc4
z1=4v3cR
z11λ
Let z2 be atomic number of impurity, z1 be atomic number of A
z21z11=λ1λ2=196169=1413
z21=26×1413=28
z2=29=10x1
x=3

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