A telephone company charges ₹0.05 per minute for local calls and ₹0.12 per minute for long distance calls. Which expression gives the total cost in rupees for " $x$ " minutes of local calls and " $y$ " minutes for long distance calls?

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Solution

Given, the charges for local and long distance calls are ₹0.05 per minute and ₹0.12 per minute respectively.
Total minutes of local call is " $x$ " minutes.
Total minutes of long distance call is " $y$ " minutes.

Therefore, the required algebraic expression is $₹ (0.05 x + 0.12 y)$

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A telephone company charges ₹0.05 per minute for local calls and ₹0.12 per minute for long distance calls. Which expression gives the total cost in rupees for "x" minutes of local calls and "y" minutes for long distance calls?

Given, the charges for local and long distance calls are ₹0.05 per minute and ₹0.12 per minute respectively. Total minutes of local call is "x" minutes. Total minutes of long distance call is "y" minutes. Therefore, the required algebraic expression is ₹(0.05x+0.12y)

A telephone company charges ₹0.05 per minute for local calls and ₹0.12 per minute for long distance calls. Which expression gives the total cost in rupees for " $x$ " minutes of local calls and " $y$ " minutes for long distance calls?

Given, the charges for local and long distance calls are ₹0.05 per minute and ₹0.12 per minute respectively.
Total minutes of local call is " $x$ " minutes.
Total minutes of long distance call is " $y$ " minutes.

Therefore, the required algebraic expression is $₹ (0.05 x + 0.12 y)$