Question

# A thin biconvex lens having refractive index 1. 5 is dipped in water having refractive index 1.33. It will behave like a .

A
convergent lens
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B
divergent lens
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C
plane mirror
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Solution

## The correct option is A convergent lensGiven: Refractive index of medium, μ1=1.33 Refractive index of lens, μ2=1.5 Let radius of curvature of the first surface be R. Then, the radius of curvature of the second surface will be −R. Using Lens Maker's Formula; 1f=(μ2μ1−1)(1R1−1R2) 1f=(1.51.3−1)(1R+1R) ⟹f>0 Since f is positive, parallel rays will form image to the right of the lens. Hence, it will behave as a convegent lens.

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