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Question

A thin equiconvex glass lens of refractive index 1.5 has power of 5D. When the lens is immersed in a liquid of refractive index μ, it acts as a divergent lens of focal length 100cm. The value of μ of liquid is

A
4/3
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B
3/4
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C
15/11
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D
8/3
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Solution

The correct option is C 15/11
Formula for focal length
1f=(μ2μ1=1)(1R11R2)
Here, 1f=50μ2=1.5μ1=1
5=(1.51)[1R11R2] ........ (1)
f=100 cm=1 m
μ2=1.5 let μ1=x
11=(1.5x1)(1R11R2) ........ (2)
Dividing (1) by (2)
51=0.51.5x1
1.5x1=0.55
1.5x=1110
x=1511μ1=1511=1.37

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