Question

A thin lens of refractive  index 1.5 has a focal length of 15 cm in air. When the lens is placed in a medium of refractive index 4/3, its focal length will become

A
30 cm
B
45 cm
C
60 cm
D
75 cm

Solution

The correct option is D 60 cmBy using $$\dfrac{f_1}{f_2}=\dfrac{(_a\mu_g-1)}{(_l\mu_g-1)} \Rightarrow f_w=4f_a=4 \times 15=60\ cm$$Physics

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