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Question

A tiger is 50 of its own leaps behind a deer. The tiger takes 5 leaps per minute to the deer's 4. If the tiger and the deer cover 8 m and 5 m per leap respectively, what distance will the tiger have to run before it catches the deer?

A
600 m
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B
700 m
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C
800 m
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D
1000 m
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Solution

The correct option is C 800 m
Speed of tiger = 40 m/min
Speed of deer = 20 m/min
Relative speed = 40 - 20 = 20 m/min
Difference in distances =50×8=400 m
Time taken in overtaking (or catching) =40020=20 min
Distance travelled in 20 min=20×40=800 m

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