A tiger is 50 of its own leaps behind a deer. The tiger takes 5 leaps per minute to the deer's 4. If the tiger and the deer cover 8 m and 5 m per leap respectively, what distance will the tiger have to run before it catches the deer?
A
600 m
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B
700 m
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C
800 m
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D
1000 m
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Solution
The correct option is C 800 m Speed of tiger = 40 m/min Speed of deer = 20 m/min Relative speed = 40 - 20 = 20 m/min Difference in distances =50×8=400m ∴ Time taken in overtaking (or catching) =40020=20min ∴ Distance travelled in 20min=20×40=800m