Question

A tile $10$ cm $\times$ $10$ cm. How many such tiles are required to cover floor $4$ m $\times$ $2.5$ m.

Answer 1

given dimensions of a tile $10cm\times 10cm$ and floor $4m\times 2.5m$

Area of floor $=4\times 2.5=10m^2$

$=10\times {10}^{4}c{m}^2$

$={10}^{5}c{m}^2$

$1filearea=10\times 10=100c{m}^2$

$\therefore$ No of files $=\frac{{10}^5}{100}=1000files.$