Question

A train starting from a railway station and moving with uniform acceleration attains a speed $40km{h}^{-1}$ in $10$ minutes. Find its acceleration.

Answer 1

Given,

Initial speed of the train $u=0$,

Final speed of the train = $40km/h=40\times \frac{5}{18}=11.11m/s$

Time $=10min$ $=10\times 60=600s$

We know that, acceleration $a=\frac{v-u}{t}$

$\Rightarrow a=\frac{11.11-0}{600}=0.0185m{s}^{-2}$.

$\therefore$ Acceleration of the train $=0.0185m{s}^{-2}$.