A train starts from rest and accelerates uniformly at a rate of $2 m s^{- 2}$ for 10 s. It then maintains a constant speed for 200 s. The brakes are then applied and the train is uniformly retarded and comes to rest in 50 s. Find the maximum velocity reached.

2 m s^{- 1}

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10 m s^{- 1}

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1 m s^{- 1}

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20 m s^{- 1}

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Solution

The correct option is D $20 m s^{- 1}$
Maximum velocity is attained at the end of uniformly accelerated motion.
From, $v = u + a t$
Maximum velocity, $v = 0 + 2 \times 10 = 20 m / s$

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A train starts from rest and accelerates uniformly at a rate of 2 ms−2 for 10 s. It then maintains a constant speed for 200 s. The brakes are then applied and the train is uniformly retarded and comes to rest in 50 s. Find the maximum velocity reached.

The correct option is D 20ms−1Maximum velocity is attained at the end of uniformly accelerated motion.From, v=u+atMaximum velocity, v=0+2×10=20 m/s

A train starts from rest and accelerates uniformly at a rate of $2 m s^{- 2}$ for 10 s. It then maintains a constant speed for 200 s. The brakes are then applied and the train is uniformly retarded and comes to rest in 50 s. Find the maximum velocity reached.

The correct option is D $20 m s^{- 1}$
Maximum velocity is attained at the end of uniformly accelerated motion.
From, $v = u + a t$
Maximum velocity, $v = 0 + 2 \times 10 = 20 m / s$