A train travelling at 20 m s -1 accelerates at 0-5 m s -2 for 30 s- How far will it travel in this time-

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Standard IX

Physics

Derivation of Velocity-Time Relation by Graphical Method

A train trave...

Question

A train travelling at 20 m s⁻¹ accelerates at 0.5 m s⁻² for 30 s. How far will it travel in this time?

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Solution

We have to find the distance travelled by the train. We have the following information given,
So, initial velocity, (u) = 20 m/s
Acceleration, (a) = 0.5 m/s²
Time taken, (t) = 30 s
We can calculate the distance travelled by using the 2^nd equation of motion,
$s = u t + \frac{1}{2} a t^{2}$
Put the values in above equation to find the distance travelled by the train,
$(s) = 20 (30) + \frac{1}{2} (0.5) (30)^{2} = (600 + 225) m = 825 m$

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A train travelling at 20 m s−1 accelerates at 0.5 m s−2 for 30 s. How far will it travel in this time?

A train travelling at 20 m s⁻¹ accelerates at 0.5 m s⁻² for 30 s. How far will it travel in this time?