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Standard X

Physics

Transformers

A transformer...

Question

A transformer consists of a coil of $1200$ turns and another coil, with a total of $120$ turns, which can be tapped at various places. Primary voltage is $240 V$ . At which pair of terminals would you connect to a $12 V, 24 W$ lamp for it to be lit normally?

N_{s} = 60

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N_{s} = 40

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N_{s} = 80

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N_{s} = 50

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Solution

The correct option is A $N_{s} = 60$
$\frac{V_{1}}{V_{2}} = \frac{N_{1}}{N_{2}}$
$= \frac{240}{12} = \frac{1200}{N_{2}}$
$= N_{2} = \frac{1200 \times 12}{240}$
$= N_{2} = 60$

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A transformer consists of a coil of 1200 turns and another coil, with a total of 120 turns, which can be tapped at various places. Primary voltage is 240 V. At which pair of terminals would you connect to a 12 V,24 W lamp for it to be lit normally?

The correct option is A Ns=60V1V2=N1N2=24012=1200N2=N2=1200×12240=N2=60

A transformer consists of a coil of $1200$ turns and another coil, with a total of $120$ turns, which can be tapped at various places. Primary voltage is $240 V$ . At which pair of terminals would you connect to a $12 V, 24 W$ lamp for it to be lit normally?

The correct option is A $N_{s} = 60$
$\frac{V_{1}}{V_{2}} = \frac{N_{1}}{N_{2}}$
$= \frac{240}{12} = \frac{1200}{N_{2}}$
$= N_{2} = \frac{1200 \times 12}{240}$
$= N_{2} = 60$