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Question

A transistor is used in common emitter configuration.Given its $$ \alpha=0.9$$,calculate the change in collector current when the base current changes by $$ 2 \mu A$$.


A
1μA
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B
9μA
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C
30μA
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D
18μA
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Solution

The correct option is B $$ 18 \mu A$$
$$\beta=\dfrac{\alpha}{1-\alpha}=\dfrac{0.9}{1-0.9}=9$$
or $$ \dfrac{\Delta I_C}{\Delta I_B}=9$$
or  $$ \dfrac{\Delta I_C}{2}=9$$
$$\therefore \Delta I_C=9\times 2=18 \mu A$$

Physics
NCERT
Standard XII

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