Question

A tree $12m$ high is broken by the wind in such a way that its top touches the ground and makes an angle ${60}^0$ with the ground. At what height from the bottom the tree is broken the wind ? $(\sqrt{3}=1.73)$

Answer 1

$\begin{array}{c}\sin {60}^{\circ }=\frac{h}{12-h}=\frac{\sqrt{3}}{2}\\ \Rightarrow \left(2+1.73\right)h=12\times 1.73\\ 3.73h=20.76\\ h=5.56m\end{array}$