A tree is brokenby wind, itsupper part touches the ground at a point 10 meters from the foot of the tree and makes an angle of 45 with the ground. The entire length of the tree is
A
15m
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B
20m
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C
10(1+√2) m
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D
10(1+√3/2) m
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Solution
The correct option is C10(1+√2) m AC = 10 = AB BC = BC' = √(102+102)=10√2 AC = AB + BC = 10 (√2 +1)