CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A triangle has sides $$5\ cm,\ 12\ cm$$ and $$13\ cm$$. Find the length of the perpendicular from the opposite vertex to the side whose length is $$13\ cm$$


Solution


$$AB\perp BC$$

$$BD\perp AC$$

$$Area(ABC)=\dfrac{1}{2}\times AB\times BC$$ (1)

$$Area(ABC)=\dfrac{1}{2}\times BD\times AC$$ (2)

Equating (1) and (2)

$$\dfrac{1}{2}\times AB\times BC=\dfrac{1}{2}\times BD\times AC$$

Let $$AB=12cm,BC=5cm,AC=13cm$$

$$ AB\times BC= BD\times AC$$ 

$$ 12\times 5= BD\times 13$$ 

$$BD=\dfrac{60}{13}$$

$$BD=4.6cm$$

The lengh of the perpendicular from the opposite vertex to the side whose length is 13 cm$$=4.6cm$$

893412_969496_ans_10b5f43c6abe43ba808a77019b2ac912.png

Maths

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image