A triangular park in a city has dimensions $30 m \times 26 m \times 28 m$ . A gardener has to plant grass inside the park at $R s .150 p e r m^{2}$ . Find the amount to be paid to the gardener.

Open in App

Solution

The dimension of the triangular park is $30 m \times 26 m \times 28 m$ .

$s = \frac{a + b + c}{2}$

$= \frac{30 + 26 + 28}{2}$

$= 42 m$

The area of the triangular park is,

$A = \sqrt{s (s - a) (s - b) (s - c)}$

$= \sqrt{42 (42 - 30) (42 - 26) (42 - 28)}$

$= 336 m^{2}$

Therefore, the amount paid to the gardener is,

$336 \times 1.50 = R s 504$

Suggest Corrections

Similar questions

Q. A triangle park in a city has dimensions

110 m \times 100 m \times 90 m

. A gardener has to plants grass inside the park at the rate of

R s 3.50

per

m^{2}

. Find the amount to be paid to gardener?

Q. A triangular park in a city has dimensions 100m X 90m X110m.A contract is given to a company for planting grass in the park at the rate of Rs.4000 per hectare.Find the amount to be paid to the company.(Take

\sqrt{2} = 1.414

)

A local park is 32 m long and its width is half of the length. It has two right-triangular grass lawns with the following dimensions. The local gardener wanted to renovate the park so he hired some men. The men agreed to work on the grass lawn at Rs. 1.2 per sq metre and put new footpath at Rs. 0.80 per sq metre. What is the total cost the gardener will have to pay after the work is done?

A triangular park ABC has sides 120 m, 80 m and 50 m. A gardener, Dhania has to put a fence all around it and also plant grass inside. The area required and the cost of fencing it with barbed wire at the rate of Rs. 20 per metre leaving a space 3 m wide for a gate on one side will be

Q. A triangular park

A B C

has sides

120 m, 80 m

and

50 m

(see figure). A gardener Dhania has to put a fence all around it and also plant grass inside. How much area does she need to plant? Find the cost of fencing it with barbed wire at the rate of

R s 20

per metre leaving a space

3 m

wide for a gate on one side ?

Join BYJU'S Learning Program

A triangular park in a city has dimensions 30m×26m×28m. A gardener has to plant grass inside the park at Rs.150perm2. Find the amount to be paid to the gardener.

The dimension of the triangular park is 30m×26m×28m. s=a+b+c2 =30+26+282 =42m The area of the triangular park is, A=√s(s−a)(s−b)(s−c) =√42(42−30)(42−26)(42−28) =336m2 Therefore, the amount paid to the gardener is, 336×1.50=Rs504

A triangular park in a city has dimensions $30 m \times 26 m \times 28 m$ . A gardener has to plant grass inside the park at $R s .150 p e r m^{2}$ . Find the amount to be paid to the gardener.