A triode has a plate resistance of $10 k Ω$ and amplification factor $24$ . If the input signal voltage is $0.4 V$ (rms), and the load resistance is $10 k Ω$ , then, the output voltage (rms) is:-

4.8 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

9.6 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12.0 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $4.8 V$
Given:-
Plate resistance $r_{p} = 10 k Ω$
Load resistance $R_{L} = 10 k Ω$
Input signal voltage $V_{s} = 0.4 V$ (rms)
Amplification factor $μ = 24$

We know that,
$V_{g a i n}, A = \frac{μ}{1 + \frac{r_{p}}{R_{L}}} = \frac{24}{1 + \frac{10 \times 10^{3}}{10 \times 10^{3}}} = 12$

Use $V_{0} = A V_{s}$
$∴$ $V_{0} = 12 \times 0.4 = 4.8 v o l t (r . m . s)$

Suggest Corrections

Similar questions

Q. A triode has a plate resistance of 10

k Ω

and amplification factor 24 . If the input signal voltage is 0.4

V (r . m . s)

, and the load resistance is

10 k Ω,

then, the output voltage(r.m.s.) is

Q. If in a triode value amplification factor is

20

and plate resistance is

10 k Ω

, then its mutual conductance is

The dynamic plate resistance of a triode valve is $10 k Ω$ Find the change in the plate current if the plate voltage is changed from 200 V and to 220 V.

Q. The plate resistance and amplification factor of a triode are 10kΩ and 20. The tube is operated at plate voltage 250 V and grid voltage −7.5 V. The plate current is 10 mA. (a) To what value should the grid voltage be changed so as to increase the plate current to 15 mA? (b) To what value should the plate voltage be changed to take the plate current back to 10 mA?

Q. The dynamic plate resistance of a triode value is 10 kΩ. Find the change in the plate current if the plate voltage is changed from 200 V to 220 V.

Join BYJU'S Learning Program

A triode has a plate resistance of 10 kΩ and amplification factor 24. If the input signal voltage is 0.4V (rms), and the load resistance is 10 kΩ, then, the output voltage (rms) is:-

The correct option is C 4.8VGiven:-Plate resistance rp=10kΩLoad resistance RL=10kΩInput signal voltage Vs=0.4V(rms)Amplification factor μ=24We know that, Vgain,A=μ1+rpRL=241+10×10310×103=12Use V0=AVs∴ V0=12×0.4=4.8volt(r.m.s)

A triode has a plate resistance of $10 k Ω$ and amplification factor $24$ . If the input signal voltage is $0.4 V$ (rms), and the load resistance is $10 k Ω$ , then, the output voltage (rms) is:-