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Standard X

Physics

Force

A truck of ma...

Question

A truck of mass 1000 kg moving with a velocity of 40 ${k m h}^{- 1}$ collides with a tree and comes to stop in 5 s. What will be the force exerted by a car on the tree?

(-) 2222 N

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(-) 2242 N

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2000 N

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(-) 2000 N

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Solution

The correct option is
A

(-) 2222 N

m = 1000 kg

u = 40 $\times$ $\frac{5}{18}$ ${m s}^{- 1}$ = $\frac{100}{9}$ ${m s}^{- 1}$

v = 0; t = 5 s

F = $\frac{m (v - u)}{t}$

F = $\frac{1000 (0 - \frac{100}{9})}{5}$

F = 200 ( $\frac{- 100}{9}$ )

F = -2222.22 N

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A truck of mass 1000 kg moving with a velocity of 40 kmh−1collides with a tree and comes to stop in 5 s. What will be the force exerted by a car on the tree?

The correct option is A (-) 2222 Nm = 1000 kg u = 40 × 518 ms−1​ = 1009 ms−1​​ v = 0; t = 5 s F = m(v−u)t F = 1000(0−1009)5 F = 200 ( −1009) F = -2222.22 N

A truck of mass 1000 kg moving with a velocity of 40 ${k m h}^{- 1}$ collides with a tree and comes to stop in 5 s. What will be the force exerted by a car on the tree?

The correct option is
A

(-) 2222 N

m = 1000 kg

u = 40 $\times$ $\frac{5}{18}$ ${m s}^{- 1}$ = $\frac{100}{9}$ ${m s}^{- 1}$

v = 0; t = 5 s

F = $\frac{m (v - u)}{t}$

F = $\frac{1000 (0 - \frac{100}{9})}{5}$

F = 200 ( $\frac{- 100}{9}$ )

F = -2222.22 N