A truck traveling due north at 50 km/hr turns west and travels at the same speed. What is the change in velocity

50 k m / h r n o r t h - w e s t

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50 \sqrt{2} k m / h r n o r t h - w e s t

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50 k m / h r s o u t h - w e s t

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50 \sqrt{2} k m / h r s o u t h - w e s t

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Solution

The correct option is D $50 \sqrt{2} k m / h r s o u t h - w e s t$
using the direction as: $N = \to j$ , $S = \to - j$ , $E = \to i$ , $W = \to - i$

${\to v}_{i}$ =50N
${\to v}_{f}$ =50W
change in velocity= ${\to v}_{f} - {\to v}_{i}$
= $50$ ( $\to - i - \to j$ )
= $50 \sqrt{2}$ $(\frac{\to - i - \to j}{\sqrt{2}})$
= $50 \sqrt{2}$ S-W

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