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Question

A tunning fork of known frequency 256 Hz makes 5 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per second when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was

A
256 + 5 Hz
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B
256 + 2 Hz
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C
256 - 2 Hz
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D
256 - 5 Hz
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Solution

The correct option is D 256 - 5 Hz
t1=256Hz
For turning fork, where f2f1=±5
f2= frequency of piano
f2=(256+5)Hz or (2565)Hz
When tension is increased the beat frequency decreases to 2 beats per second. If we assume that frequency of piano string is 261Hz. Then on increasing tension frequency, more than 261Hz. But it is given that beat frequency decreases, therefore 261Hz is not post.
(2565)Hz

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