Question

# A tunning fork of known frequency 256 Hz makes 5 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per second when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was

A
256 + 5 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
256 + 2 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
256 - 2 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
256 - 5 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D 256 - 5 Hzt1=256HzFor turning fork, where f2−f1=±5f2= frequency of pianof2=(256+5)Hz or (256−5)HzWhen tension is increased the beat frequency decreases to 2 beats per second. If we assume that frequency of piano string is 261Hz. Then on increasing tension frequency, more than 261Hz. But it is given that beat frequency decreases, therefore 261Hz is not post.∴(256−5)Hz

Suggest Corrections
0
Related Videos
Normal Modes on a String
PHYSICS
Watch in App
Explore more