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Question

A uniform chain of mass M and length L lies on a horizontal table such that one third of its length hangs from the edge of the table. The work done is pulling the hanging part on the table will be?

(with explaination plz)


Solution

  Work Done = mass of chain hanged * g * distance of chain from centre of mass of hanged part of chain
So, work done = M/3 * g * L/(3*2)
                (This length is taken L/6 NOT L/3 becoz distance is taken from centre of mass,height that you raise the center of mass is 1/2 the length, which makes L/6 not L/3
)
So, WORK DONE = MgL/18

hope it helps

 

Physics

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