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Question

A uniform circular disc of radius R is rotating about its own axis with moment of inertia I at an angular velocity ω. If a dense particle of mass m is gently attached to the rim of disc than its angular velocity is :

A
ω
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B
Iw(I+mR)
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C
I+mR2Iw
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D
IwI+mR2
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Solution

The correct option is D IwI+mR2
Initial moment of inertia =I
Final moment of inertia, I1=I+mR2

Using conservation of angular momentum
we have Iω=(I+mR2)ω1
ω1=IωI+mR2

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