Question

# A uniform conductor of resistance R is cut into $$20$$ equal pieces half of them are joined is series and the remaining half of them are connected in parallel if the two combination are joined in series

Solution

## let the resistance of each piece $${ R }_{ 0 }$$where$${ R }_{ 0 }$$ $$R/20$$so we have 10 such resistance joined in resistance thus giving us an $${ R }_{ eq\quad series }=10\times { R }_{ 0 }=10{ R }_{ 0 }$$the 10 resistance joined in parallel which gives us an equilance $${ R }_{ eq\quad parallel }=10/{ R }_{ 0 }\quad this\quad combination\quad joined\quad in\quad series\quad { R }_{ net\quad }={ R }_{ 0 }/10=10{ R }_{ 0 }$$$${ R }_{ net\quad }=101{ R }_{ 0 }/10=101\times R/200$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More