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Question

A uniform conductor of resistance R is cut into 20 equal pieces half of them are joined is series and the remaining half of them are connected in parallel if the two combination are joined in series

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Solution

let the resistance of each piece R0
whereR0 R/20
so we have 10 such resistance joined in resistance thus giving us an Reqseries=10×R0=10R0
the 10 resistance joined in parallel which gives us an equilance
Reqparallel=10/R0thiscombinationjoinedinseriesRnet=R0/10=10R0
Rnet=101R0/10=101×R/200

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