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Question

A uniform cord of length 6.0 m and 12.0 kg is shown in the figure with a block of 3.0 kg suspended from it. Find the speed of the pulse on the horizontal part of the cord.


  1. 4.4 m/s
  2. 15 m/s
  3. 5 m/s
  4. 12 m/s


Solution

The correct option is C 5 m/s
V=Th 

T = mg + weight of hanging cord

=30+16×12×10

=30+20=50 N  

h=ml=126=2 kg/m

v=Th=502=25=5 m/s

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