CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A uniform magnetic field B points vertically up and is slowly changed in magnitude, but not in direction. The rate of change of the magnetic field is $$\alpha$$. A conducting ring of radius r and resistance R is held perpendicular to the magnetic field and is totally inside it. The induced current in the ring is then


A
zero
loader
B
2πrBR
loader
C
rαR
loader
D
πr2αR
loader

Solution

The correct option is B $${\dfrac{\pi r^{2}\alpha}{R}}$$

given:
Rate of change of magnetic field $$\dfrac{dB}{dt}=\alpha$$

The magnitude of induced emf is:$$|\epsilon|$$  
  $$=\dfrac{d\phi}{dt}\\=\dfrac{d}{dt}{BA}\\=A\dfrac {dB}{dt}\\=\pi r^2\alpha$$


The induced current in the ring, $$\displaystyle I=\frac{|\epsilon|}{R}=\frac {\pi r^2 \alpha}{R}$$

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image