    Question

# A uniform metallic wire of resistance $18\Omega$ is bent to form equilateral triangle as shown in figure. Find the equivalent resistance of the resulting connection A

$8\Omega$

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B

$12\Omega$

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C

$4\Omega$

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D

$2\Omega$

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Solution

## The correct option is C $4\Omega$Explanation for the correct option: Solving for Equivalent resistanceSince it is an equilateral triangle, ${R}_{1}={R}_{2}={R}_{3}=6\Omega$The circuit can be redrawn as :As the $2$ resistances are in series the equivalent for them is ${R}_{s}=6+6=12\Omega$ The equivalent resistance is,$\frac{1}{{R}_{eq}}=\frac{1}{12}+\frac{1}{6}$${R}_{eq}=\frac{12}{1+2}=\frac{12}{3}=4\Omega$Hence, option C is correct.  Suggest Corrections  1      Similar questions
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