A uniform rectangular thin sheet ABCD of mass M has length a and breadth b, as shown in the figure. If the shaded portion HBGO is cut-off, the coordinates of the centre of mass of the remaining portion will be :-
A
(2a3,2b3)
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B
(5a3,5b3)
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C
(3a4,3b4)
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D
(5a12,5b12)
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Solution
The correct option is D(5a12,5b12) x=Ma2−M4×3a4M−M4 =a2−3a1634=5a1634=5a12 y=Mb2−M4×3b4M−M4=5b12