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Question

A uniform rod of mass 5 kg and length 3 m is held at an angle θ=37 with the horizontal as shown in the figure. The potential energy of the rod is (in J)


  1. 9g2
  2. 12g
  3. 6g
  4. 21g2


Solution

The correct option is A 9g2

For uniform linear body
Potential energy, U=mgh
where m=5 kg
h= distance of centre of mass from ground =l2sinθ=32sinθ
=3sinθ2

U=3mgsinθ2, where m=5 kg, θ=37
U=9g2 J

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