Question

# A uniform rope of mass M and length L is accelerated upwards with acceleration ′a′ by applying force on the topmost point. What is the tension in the rope at a distance X from the lower end?

A
ML×a
B
MLX(g+a)
C
ML(LX)a
D
None

Solution

## The correct option is B MLX(g+a)We assume the tension ′T′ at distance X from lower end. Mass of the lower portion of length X is ′m′. Since the rope is uniform, therefore mass per unit length remains same for every section. m=(ML)X F.B.D of lower portion. T−mg=ma T=m(g+a) T=MLX(g+a)

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