CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A unit vector perpendicular to the plane of a=2^i6^j3^k,b=4^i+3^j^k is

A
4^i+3^j^k26
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2^i6^j3^k7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3^i2^j+6^k7
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2^i3^j6^k7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 3^i2^j+6^k7
a×b=∣ ∣ ∣^i^j^k263431∣ ∣ ∣=^i(6+9)^j(2+12)+^k(6+24)=15^i10^j+30^k
|a×b|=225+100+900=35
Unit vector normal to the plane = 15^i10^j+30^k35=3^i2^j+6^k7

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Vector Product
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon