A vegetable vendor cabbages, priced according to how much each cabbage weighs. The first seven ounces cost $25$ cents each, and each additional ounce costs $15$ cents. If $p (c)$ is the price in dollars of a cabbage weighing c ounces, with $c \geq 7$ , then which of the following is $p (c)$ ?

p (c) = 175 + 15 c

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p (c) = .25 + .15 c

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p (c) = .25 + .15 (c - 7)

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p (c) = 1.75 + .15 (c - 7)

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p (c) = 1.75 + .15 c

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Solution

The correct option is C $p (c) = 1.75 + .15 (c - 7)$
The cost of first $7$ ounces is $7 \times 0.25 = 1.75$
The total number of ounces is $c$
So the cost of remaining $c - 7$ ounces is $0.15 (c - 7)$
Therefore the total cost is $p (c) = 1.75 + 0.15 (c - 7)$
So the correct option is $D$

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A vegetable vendor cabbages, priced according to how much each cabbage weighs. The first seven ounces cost 25 cents each, and each additional ounce costs 15 cents. If p(c) is the price in dollars of a cabbage weighing c ounces, with c≥7, then which of the following is p(c)?

The correct option is C p(c)=1.75+.15(c−7)The cost of first 7 ounces is 7×0.25=1.75The total number of ounces is cSo the cost of remaining c−7 ounces is 0.15(c−7)Therefore the total cost is p(c)=1.75+0.15(c−7)So the correct option is D

A vegetable vendor cabbages, priced according to how much each cabbage weighs. The first seven ounces cost $25$ cents each, and each additional ounce costs $15$ cents. If $p (c)$ is the price in dollars of a cabbage weighing c ounces, with $c \geq 7$ , then which of the following is $p (c)$ ?

The correct option is C $p (c) = 1.75 + .15 (c - 7)$
The cost of first $7$ ounces is $7 \times 0.25 = 1.75$
The total number of ounces is $c$
So the cost of remaining $c - 7$ ounces is $0.15 (c - 7)$
Therefore the total cost is $p (c) = 1.75 + 0.15 (c - 7)$
So the correct option is $D$