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Question

A vertical rectangular coil of sides 5cm×2cm has 10 turns and carries a current of 2A. The torque(couple) on the coil when it is placed in a uniform horizontal magnetic field of 0.1T with its plane perpendicular to the field is

A
4×103Nm
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B
0
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C
2×103Nm
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D
103Nm
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Solution

The correct option is D 0
If plane is perpendicular to the field, normal vector will be parallel to field
sinθ=0
J=MBsinθ=0

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