CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A very long magnet is placed vertically with one pole on the table. A neutral point was found at 20cm from the pole. What is the pole strength if the vertical component of earth's field is 0.4×104Wbm2?

A
16Am
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
8Am
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4Am
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 16Am
Magnetic field due to pole of strength m at distance d is
B=μ0m4πd2
Vertical component of earth's magnetic field =0.4×104Wbm2
At the neutral point, μ0m4πd2=0.4×104
m=16Am

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon